solo_guitar Joined Aug 22, 2024 Messages 62 Reaction score 6 Sep 11, 2024 #1 See attachment. Find area of shaded region. Try this one. Attachments 20240911_122906.jpg 239.8 KB · Views: 15
Oculus8596 Joined Sep 16, 2024 Messages 25 Reaction score 0 Location Great Lakes, Illinois Sep 17, 2024 #2 solo_guitar said: See attachment. Find area of shaded region. Try this one. Click to expand... The hypotenuse is the diagonal of the square in the circle. The hypotenuse = 2•sqrt{2}. Radius = Diameter ÷ 2 R = 2•sqrt{2}/2 R = sqrt{2} The area of the circle is all that we need. A = pi•R^2 A = pi•(sqrt{2})^2 A = 2•pi Done!
solo_guitar said: See attachment. Find area of shaded region. Try this one. Click to expand... The hypotenuse is the diagonal of the square in the circle. The hypotenuse = 2•sqrt{2}. Radius = Diameter ÷ 2 R = 2•sqrt{2}/2 R = sqrt{2} The area of the circle is all that we need. A = pi•R^2 A = pi•(sqrt{2})^2 A = 2•pi Done!