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Find k for 114. Something tells me to use the radicand of the quadratic formula. Yes?
Didn't you just post this?
"Find k so that x^2- kx+ 4= 0 has a repeated real solution."
A quadratic equation has a repeated solution if and only if it is of the form (x- a)^2= 0 for some a. What must "a" be for x^2- kx+ 4= 0? So what is k?
It's not that complicated! (x- a)^2= x^2- 2ax+ a^2. Comparing that to x^2- kx+ 4, we see that a^2= 4 so a is either 2 or -2 and so k is either 4 or -4. Of course if k= -4, that would be x^2+ 4x+ 4 so they probably would not have written "-kx". I suspect k= 4 was intended.