Find Numbers k

[nycmathguy]

College Algebra
Section R.4

 

[MathLover1]

107.

(3x-2k)(4x+3k)=12x^2+kx-96

12x^2+ kx -6 k^2=12x^2+kx-96.........simplify
-6k^2=-96
k^2=-96/ -6
k^2=16
k=4
k=-4

 

[nycmathguy]

107.

(3x-2k)(4x+3k)=12x^2+kx-96

12x^2+ kx -6 k^2=12x^2+kx-96.........simplify
-6k^2=-96
k^2=-96/ -6
k^2=16
k=4
k=-4

I see that it really isn't much of a challenge.