I want to know if the set up is correct. There are three consecutive odd integers. Three times the largest is seven times the smallest. Find the integers. Set Up: Three consecutive odd integers: 2n + 1, 2n + 3, 2n + 5. Let 2n + 5 = largest integer. Let 2n + 1 = smallest integer. 3(2n + 5) = 7(2n + 1) Yes?