Find x-and y-Intercepts...2

[nycmathguy]

Question 26

y = sqrt{2x - 1}

Let x = 0

y = sqrt{2(0) - 1}

y = sqrt{0 - 1}

y = sqrt{-1}

The sqrt{-1} = I.

I will say no y-intercept over the real numbers.

Let y = 0

0 = sqrt2x - 1 }

(0)^2 = [sqrt{2x - 1}]^2

0 = 2x - 1

1 = 2x

1/2 = x

The x-intercept is 1/2.

 

[MathLover1]

, you should write i, not I

answer: correct

 

[nycmathguy]

View attachment 3443 , you should write i, not I

answer: correct

The keyboard on my phone does not always display a lower case letter i.