[QUOTE="MathLover1,
Question 22
y = x^3 + x^2 - 3x
Let x = 0
y = (0)^3 + (0)^2 - 3(0)
y = 0.
Our y-intercept is found at the point (0, 0) aka the origin. The graph shows this to be true.
Let y = 0
0 = x^3 + x^2 - 3x
0 = x(x^2 + x - 3)
Set each factor to 0 and solve for x.
I see that x = 0 is one of the x-intercept found at the point (0,0). This graph shows this to be true.
x^2 + x - 3 = 0
By the quadratic formula, I found two more x-intercepts.
x = -(1/2) - sqrt13}/2
x = sqrt{13}/2 - (1/2)
The graph shows this to be true as well.
