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Question 24

x^3 + x^2 y = 12

Let x = 0

(0)^3 + (0)^2 y = 12

0 + 0 does not equal 12. I conclude there are no y-intercepts. The graph shows this to be true.

Let y = 0

x^3 + x^2 (0) = 12

x^3 = 12

Let cr = cube root

cr{x^3} = cr{12}

x = 2.2894284851

Rounding to two decimal places, I get 2.29.
The graph shows this to be true as the graph crosses the x-axis slightly to the right of 2.

You say?

[QUOTE="nycmathguy, post: 1096267, member: 279"] Question 24 x^3 + x^2 y = 12 Let x = 0 (0)^3 + (0)^2 y = 12 0 + 0 does not equal 12. I conclude there are no y-intercepts. The graph shows this to be true. Let y = 0 x^3 + x^2 (0) = 12 x^3 = 12 Let cr = cube root cr{x^3} = cr{12} x = 2.2894284851 Rounding to two decimal places, I get 2.29. The graph shows this to be true as the graph crosses the x-axis slightly to the right of 2. You say? [/QUOTE]