Granular Angle of Repose

[nycmathguy]

Section 4.7

Part (a)

I will do the set up only.

cot(theta) = 5.5/8.5

Taking arccot on both sides, I get the following:

theta = arccot(5.5/8.5)

Yes?

Part (b)

After finding theta for (a), here is the set up:

tan(theta found in part a) = h/8.5, where h is the height of a pile of rock salt.

You say?

 

[MathLover1]

Part (a) cot(theta) = 5.5/8.5.......incorrect

it is tan(theta) = 5.5/8.5

 

[nycmathguy]

Part (a) cot(theta) = 5.5/8.5.......incorrect

it is tan(theta) = 5.5/8.5

I meant to type tan(theta) but for some reason cot(theta) came to mind. I got it. Not too bad. Wish all problems were this easy.