Graph of Projectile Motion

[nycmathguy]

See attachment.

Part (a)

I say h is a function of t because the value of h depends on the value of t. So, t is the independent variable and h is the dependent variable.

Part (b)

The height of the projectile after 0.5 seconds is 20 feet.

The height of the projectile after 1 25 seconds is 25 feet.

Part (c)

The domain of h is [0, 2.5].

Part (d)

Part (a) above tells us that h is a function of t and not vice-versa. Part (a) also gives us a precise reason why t cannot be a function of h.

You say?

 

[MathLover1]

See attachment.

Part (a)

I say h is a function of t because the value of h depends on the value of t. So, t is the independent variable and h is the dependent variable.

Part (b)

The height of the projectile after 0.5 seconds is 20 feet.

The height of the projectile after 1 25 seconds is 25 feet.

Part (c)

The domain of h is [0, 2.5].

Part (d)

Part (a) above tells us that h is a function of t and not vice-versa. Part (a) also gives us a precise reason why t cannot be a function of h.

You say?

View attachment 60

my preference and correction
Part (a)
h is a function of t, because for each input h , there is only one output t
that graph will pass vertical line test=> h is a function of t

Part (b)

correction for the height of the projectile after 1. 25 seconds

it is 30 feet (look for 1. 25 which is half way between 1.0 and 1.5)

 

[nycmathguy]

my preference and correction
Part (a)
h is a function of t, because for each input h , there is only one output t
that graph will pass vertical line test=> h is a function of t

Part (b)

correction for the height of the projectile after 1. 25 seconds

it is 30 feet (look for 1. 25 which is half way between 1.0 and 1.5)

Ok. Is my domain correct?

 

[MathLover1]

Ok. Is my domain correct?

rest is correct

 

[nycmathguy]

rest is correct

Very cool. I may post a few more questions from Section 1.5 later on today. In any case, Happy 4th of July to you and your family.