Half-Angle Formulas...3

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Jan 1, 2022.

  1. nycmathguy

    nycmathguy

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    Section 5.5

    Screenshot_20211231-174444_Samsung Notes.jpg

    IMG_20211231_195927.jpg

    IMG_20211231_195940.jpg

    IMG_20211231_195954.jpg
     
    nycmathguy, Jan 1, 2022
    #1
  2. nycmathguy

    MathLover1

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    answer is -2 - sqrt(3)

    tan(7pi/12)=sin(7pi/6)/(1+cos(7pi/6))
    tan(7pi/12)=(-1/2)/(1-sqrt(3)/2)
    tan(7pi/12)=-1/(2(1-sqrt(3)/2)
    tan(7pi/12)=-1/(2-sqrt(3))......rationalize
    tan(7pi/12)=-(2+sqrt(3))/(((2-sqrt(3))(2+sqrt(3)))
    tan(7pi/12)=-(2+sqrt(3))/(1)
    tan(7pi/12)=-(2+sqrt(3))
    tan(7pi/12)=-2-sqrt(3)
     
    MathLover1, Jan 1, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Another sign error. Cool. Take away a few points.
     
    nycmathguy, Jan 1, 2022
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    MathLover1 likes this.
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