# Horizontal Asymptotes

Discussion in 'Other Pre-University Math' started by nycmathguy, Sep 21, 2021.

1. ### nycmathguy

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Section 2.6
10, 12, 14, 16 Q. 10

The numerator is 1, which can be expressed as 1•x^0. The degree of the numerator is smaller than the degree of the denominator. The horizontal asymptote is the line y = 0.

Q. 12

The degree of the numerator = degree of denominator. The horizontal asymptote is -7/2 for this question.

Q. 14

The degree of the numerator > degree of denominator. So, no horizontal asymptote.

Q. 16

The degree of the numerator = degree of the denominator. So, the horizontal asymptote is
-4/1 or simply -4.

You say?

nycmathguy, Sep 21, 2021

2. ### MathLover1

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Q. 10

The horizontal asymptote is the line y = 0-> correct
The vertical asymptote is the line x =2 12.
Vertical: x=- 3/2
Horizontal: y=-7/2 -> you did it correct

Q. 14
no horizontal asymptote=> correct
Vertical: x= -2

Q. 16
correct

MathLover1, Sep 21, 2021
nycmathguy likes this.

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