Horizontal Asymptotes

Discussion in 'Other Pre-University Math' started by nycmathguy, Sep 21, 2021.

  1. nycmathguy

    nycmathguy

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    Section 2.6
    10, 12, 14, 16
    20210920_234355.jpg

    Q. 10

    The numerator is 1, which can be expressed as 1•x^0. The degree of the numerator is smaller than the degree of the denominator. The horizontal asymptote is the line y = 0.

    Q. 12

    The degree of the numerator = degree of denominator. The horizontal asymptote is -7/2 for this question.

    Q. 14

    The degree of the numerator > degree of denominator. So, no horizontal asymptote.

    Q. 16

    The degree of the numerator = degree of the denominator. So, the horizontal asymptote is
    -4/1 or simply -4.

    You say?
     
    nycmathguy, Sep 21, 2021
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  2. nycmathguy

    MathLover1

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    Q. 10

    The horizontal asymptote is the line y = 0-> correct
    The vertical asymptote is the line x =2
    upload_2021-9-21_13-22-32.png


    12.
    Vertical: x=- 3/2
    Horizontal: y=-7/2 -> you did it correct

    Q. 14
    no horizontal asymptote=> correct
    Vertical: x= -2

    Q. 16
    correct
     
    MathLover1, Sep 21, 2021
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    nycmathguy likes this.
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  3. nycmathguy

    nycmathguy

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    Precalculus is getting interesting, to say the least. I thank you for taking the ride with me.
     
    nycmathguy, Sep 21, 2021
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