Section 2.6\n10, 12, 14, 16\n[ATTACH=full]486[/ATTACH] \n\nQ. 10\n\nThe numerator is 1, which can be expressed as 1•x^0. The degree of the numerator is smaller than the degree of the denominator. The horizontal asymptote is the line y = 0.\n\nQ. 12\n\nThe degree of the numerator = degree of denominator. The horizontal asymptote is -7/2 for this question. \n\nQ. 14\n\nThe degree of the numerator > degree of denominator. So, no horizontal asymptote.\n\nQ. 16\n\nThe degree of the numerator = degree of the denominator. So, the horizontal asymptote is \n-4/1 or simply -4.\n\nYou say?