Intermediate Value Theorem...3

Joined
Jun 27, 2021
Messages
5,386
Reaction score
422
Calculus
Section 2.5

Screenshot_20220516-084404_Samsung Notes.jpg


IMG_20220523_102859.jpg


Screenshot_20220523-102320_Samsung Internet.jpg


This graph is generated by Wolfram.
 
it is the Lambert W-function

x=- (2W0(e^(3/2)/2)-3)/2
Decimal: x=0.59420 => which is between -2 and 1,718

here is more about Lambert W-function

https://mathworld.wolfram.com/LambertW-Function.html

You said the Lambert x-value in decimal form is 0.59420, which lies between f(0) and f(1). However, 0.59420 is not between the given open interval
(0, 1). I don't think x = 0.59420 is the answer.

You say?
 
0< 0.59420<1, so x = 0.59420 is the answer

You are right. We are seeking for a solution that lies between the given interval not between f(0) and f(1). Overall, this is not too bad. I don't understand the importance of this theorem. However, I do like the fact that it becomes straightforward after solving a few problems.
 

Members online

No members online now.

Forum statistics

Threads
2,521
Messages
9,844
Members
694
Latest member
FannyTurnb
Back
Top