Law of Sines...2

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Jan 8, 2022.

  1. nycmathguy

    nycmathguy

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    Section 6.1

    Screenshot_20220108-171902_Samsung Notes.jpg

    IMG_20220108_173010.jpg

    IMG_20220108_173020.jpg

    IMG_20220108_173031.jpg
     
    nycmathguy, Jan 8, 2022
    #1
  2. nycmathguy

    MathLover1

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    <B=15 degrees 30'=15.5°
    a=4.5
    b=6.8

    a/sinA=b/sinB=c/sinC

    use given to find side c and angles A and C

    a/sin(A)=b/sin(B)

    4.5/sin(A)=6.8/sin(15.5)

    sin(A)=(4.5*sin(15.5))/6.8

    sin(A)=(4.5*0.267238)/6.8

    sin(A)=0.17684867647058822

    A=sin^-1(0.17684867647058822)

    A=10.186257639823903°

    A=10° 11‘

    then angle C=180-(15° 30‘+10° 11‘)=154° 19'

    find side c

    c/sin(C)=b/sin(B)

    c=(6.8/sin(15° 30‘))*sin(154° 19' )

    c=(6.8/0.267238376)*0.4333969535634

    c=(25.445447251183715)*0.4333969535634

    c=11.03
     
    MathLover1, Jan 9, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    I understand the gist of the law of sines so far. Wish I had time to work out all the problems but time is limited. I think my problem has been lack of focus. You see, I only have the weekend to work out most of the questions per section. I also make time for my guitar and personal errands.
     
    nycmathguy, Jan 9, 2022
    #3
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