Limits of Piecewise Functions...5

Discussion in 'Calculus' started by nycmathguy, Apr 7, 2022.

  1. nycmathguy

    nycmathguy

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    Calculus



    Screenshot_20220404-195404_Samsung Internet.jpg

    In order for the limit to exists, the following must take place:

    lim (x - 3) as x tends 0 from the left = lim (x + 1) as x tends to 0 from the right.

    Let x = 0.

    (x - 3) = (x + 1)

    (0 - 3) = (0 + 1)

    -3 DOES NOT EQUAL 1.

    So, I can now say that the limit of f(x) as x tends to 0 DNE.
     
    nycmathguy, Apr 7, 2022
    #1
  2. nycmathguy

    MathLover1

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    correct
     
    MathLover1, Apr 7, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Beautiful. I'm cooking with gas. Ha!
     
    nycmathguy, Apr 7, 2022
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