Limits of Piecewise Functions...6

Calculus




In order for the limit to exists, the following must take place:

lim (2x + 8) as x tends -2 from the left = lim (x^2) as x tends to -2 from the right.

Let x = -2.

(2x + 8) = (x^2)

(2(-2) + 8) = (-2)^2

4 = 4

So, I can now say that the limit of f(x) as x tends to -2 is 4.

 

correct

 

A happy man am I.