Log Prove

[nycmathguy]

 

[MathLover1]

log(b,((sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2)))=2log(b(sqrt(3)+sqrt(2))

log(b,((sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2)))

=>(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))........rationalize, multiply (sqrt(3)+sqrt(2))

=((sqrt(3)+sqrt(2))((sqrt(3)+sqrt(2))))/((sqrt(3) - sqrt(2))(sqrt(3)+sqrt(2)))

=(((sqrt(3)+sqrt(2))^2)/((sqrt(3) )^2- (sqrt(2))^2))

=((sqrt(3)+sqrt(2))^2)/(3- 2)

=((sqrt(3)+sqrt(2))^2)/1

=(sqrt(3)+sqrt(2))^2

then

log(b,(sqrt(3)+sqrt(2))^2 =2log(b,(sqrt(3)+sqrt(2))->proven

 

[nycmathguy]

log(b,((sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2)))=2log(b(sqrt(3)+sqrt(2))

log(b,((sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2)))

=>(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))........rationalize, multiply (sqrt(3)+sqrt(2))

=((sqrt(3)+sqrt(2))((sqrt(3)+sqrt(2))))/((sqrt(3) - sqrt(2))(sqrt(3)+sqrt(2)))

=(((sqrt(3)+sqrt(2))^2)/((sqrt(3) )^2- (sqrt(2))^2))

=((sqrt(3)+sqrt(2))^2)/(3- 2)

=((sqrt(3)+sqrt(2))^2)/1

=(sqrt(3)+sqrt(2))^2

then

log(b,(sqrt(3)+sqrt(2))^2 =2log(b,(sqrt(3)+sqrt(2))->proven

Is it possible for you to use LaTex or write your reply on paper and then upload here for easy reading?

 

[MathLover1]

manipulate left side

=> rationalize,

, multiply by

=

=

=

=

=

substitute in log

=

->proven

 

[nycmathguy]

manipulate left side

=> rationalize,

, multiply by

=

=

=

=

=

substitute in log

=

->proven

1. Is this LaTex?

2. If not LaTex, what app did you use to type this reply?

3. Reply using this style of writing from now on. It's a lot easier to read and understand.

 

[MathLover1]

it's wolframalpha

 

[nycmathguy]

it's wolframalpha

How does wolframalpha work? Do you pay for this service? See your PM.