Long Division

[nycmathguy]

 

[MathLover1]

\( f(x)=x^3-4x^2-5 \)

find \(f(x) /(x-3)\)

________(\(x^2-x-3\)
\((x-3)| x^3-4x^2+0*x-5 \)
......... \(x^3-3x^2\) .................subtract
................. \(-x^2+0*x\) ........................bring down +\(0*x\)
.................\( -x^2+3x \)..subtract
......................... \(-3x\) .............bring down \( -5\)
.........................\( -3x-5\)
.........................\( -3x+9\) .......subtract
..............................\(-14 -\)>reminder

=> \( f(x) /(x-3)=x^2-x-3+(-14/(x-3))\)

or,

\(x^3 - 4 x^2 - 5 = (x^2 - x - 3)(x - 3) -14\)

 

[nycmathguy]

\( f(x)=x^3-4x^2-5 \)

find \(f(x) /(x-3)\)

________(\(x^2-x-3\)
\((x-3)| x^3-4x^2+0*x-5 \)
......... \(x^3-3x^2\) .................subtract
................. \(-x^2+0*x\) ........................bring down +\(0*x\)
.................\( -x^2+3x \)..subtract
......................... \(-3x\) .............bring down \( -5\)
.........................\( -3x-5\)
.........................\( -3x+9\) .......subtract
..............................\(-14 -\)>reminder

=> \( f(x) /(x-3)=x^2-x-3+(-14/(x-3))\)

or,

\(x^3 - 4 x^2 - 5 = (x^2 - x - 3)(x - 3) -14\)

Sorry but I could not follow your steps. Can you do this one on paper and then upload?

 

[MathLover1]

steps in one example:

Step 1: Set up the long division.
Step 2: Divide 1st term of dividend by first term of divisor to get first term of the quotient.
Step 3: Take the term found in step 2 and multiply it times the divisor.
Step 4: Subtract this from the line above.
Step 5: Repeat until done.
Step 6: Write out the answer.

answer is:

or

 

[nycmathguy]

steps in one example:

Step 1: Set up the long division.
Step 2: Divide 1st term of dividend by first term of divisor to get first term of the quotient.
Step 3: Take the term found in step 2 and multiply it times the divisor.
Step 4: Subtract this from the line above.
Step 5: Repeat until done.
Step 6: Write out the answer.

answer is:

or

It now came back to me. Thanks.