[ATTACH=full]2088[/ATTACH]
\( f(x)=x^3-4x^2-5 \) find \(f(x) /(x-3)\) ________(\(x^2-x-3\) \((x-3)| x^3-4x^2+0*x-5 \) ......... \(x^3-3x^2\) .................subtract ................. \(-x^2+0*x\) ........................bring down +\(0*x\) .................\( -x^2+3x \)..subtract ......................... \(-3x\) .............bring down \( -5\) .........................\( -3x-5\) .........................\( -3x+9\) .......subtract ..............................\(-14 -\)>reminder => \( f(x) /(x-3)=x^2-x-3+(-14/(x-3))\) or, \(x^3 - 4 x^2 - 5 = (x^2 - x - 3)(x - 3) -14\)
steps in one example: Step 1: Set up the long division. Step 2: Divide 1st term of dividend by first term of divisor to get first term of the quotient. Step 3: Take the term found in step 2 and multiply it times the divisor. Step 4: Subtract this from the line above. Step 5: Repeat until done. Step 6: Write out the answer. answer is: or