48.
b. product in trigonometric form
3i(1-sqrt(2)*i)
use 3i and (1-sqrt(2)*i),
in trig. form they are
z=3(cos(pi/2)+i*sin(pi/2))..........1)
z=sqrt(3)(cos(-0.955316618)+i*sin(-0.955316618))..........2)
multiply 1) and 2)
3(cos(pi/2)+i*sin(pi/2))*sqrt(3)(cos(-0.955316618)+i*sin(-0.955316618))=4.24264+3* i
c.
product in standard form (I actually did it first time)
3i(1-i*sqrt(2)*i)=3i-3i*sqrt(2)*i=3sqrt(2) + 3 i=4.24264+ 3i
so, result is same
you can do 50 same way
