Section 6.2 Can you do 51 for me? [ATTACH=full]1701[/ATTACH]

51. The bearing of 2 last legs of race are angels A and C Applying the Law of cosine we have: cos(C)= (a² + b² -c²)/(2ab) cos(C)= (1700² + 3000² -3700²)/(2*1700*3000) cos(C)=(11890000-13690000)/10200000 cos(C)=-3/17 C=cos^-1(-3/17) C=100.2° cos(A) = (b^2 + c^2 - a^2)/(2bc) cos(A) = (3000^2 +3700^2 - 1700^2)/(2*3000*3700) cos(A) = 33/37 A=cos^-1(33/37) A=26.89° The last two bearings are 26.89° and 100.2°

You said: "The bearing of 2 last legs of race are angels A and C." I know you meant to say angles not angels. What in the question indicates this fact about angles A and C?

race starts at B, continues to C (bearing first time), continues to A (bearing second time), continues back to B