nth Root of Complex Number...2

[nycmathguy]

Section 6.6

 

[MathLover1]

 

[nycmathguy]

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How did you get r = 4, and theta = 0?

 

[MathLover1]

The polar form of -4 is 4 (cos(pi ) + i *sin(pi))

->should be r=4, and θ = π (above was mistake, I just put value of sin(π) which gives you θ =0)

so, answer will change and should be:

answer:

 

[nycmathguy]

The polar form of -4 is 4 (cos(pi ) + i *sin(pi))

->should be r=4, and θ = π (above was mistake, I just put value of sin(π) which gives you θ =0)

so, answer will change and should be:

View attachment 2124

answer:

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Is this not what I got? I am correct. Yes?

 

[MathLover1]

yes, it is correct

 

[nycmathguy]

yes, it is correct

Can you please go back and check my answers again to the other nth roots of complex numbers threads? I am almost sure I got the others right, too. Going to bed now. Back to work tonight.