Oscillation of a Spring

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Section 4.8

This is our last question for this section.
Note: Moving forward less questions per section will be the focus. The goal is to understand the concept behind each topic. Once the concept is understood, answering questions becomes a lot easier, I think. You say?

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Part (a)

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Is there am easier way to express the answer for part (c)?

We now move on to Chapter 5.
 
way to express the answer for part (c)

t = (π n)/16 - π/32, n element Z
substitute n=1
t = (π*1)/16 - π/32
t = π/16 - π/32
t = 2π/32 - π/32
t=π/32
t≈0.09817477
 
way to express the answer for part (c)

t = (π n)/16 - π/32, n element Z
substitute n=1
t = (π*1)/16 - π/32
t = π/16 - π/32
t = 2π/32 - π/32
t=π/32
t≈0.09817477

Is part (b) correct?

We move on to Chapter 5 aka Analytic Trigonometry. In Chapter 5, we tackle trigonometric identities and yes, more word problems. By the way, I love trigonometric identities.

Remember: There will be less questions moving forward to focus more on the concept behind each topic. In fact, I think it was you who stated a few weeks ago that learning the concept or idea leads to answering more questions correctly. So, I guess this is what we'll do.

It is my hope that you will stick around as we make our way to Calculus l. I expect to be in the James Stewart calculus textbook by early April or late March. Let's see what happens. Life is unpredictable.
 

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