Properties of Exponents

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Section 3.1
Question 69

How is this done?
Do 69 and I will try 70.

20211012_194735.jpg
 
70. it ask you to find option (IF ANY) are same; so, no answer option is same as any of g(x)

in case we have 4^(x+12)=2^(2(x+12))=2^(2x+24), there is still no option for g(x)

71. use rule 4. a^-n=1/a^n...since you have to multiply by 16, you will have 16a^-n=16(1/a^n)

72. same case as 71; so, no answer option is same as any of g(x)
 
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70. it ask you to find option (IF ANY) are same; so, no answer option is same as any of g(x)

in case we have 4^(x+12)=2^(2(x+12))=2^(2x+24), there is still no option for g(x)

71. use rule 4. a^-n=1/a^n...since you have to multiply by 16, you will have 16a^-n=16(1/a^n)

72. same case as 71; so, no answer option is same as any of g(x)

For 71, f(x) = h(x).

16(4^-x)

16(2^2(-x))

16(2^(-2x))

You say?

Note: We are done with Section 3.1.
We move on to Logarithmic Functions.
 

Interesting questions. First time for me. Keep in mind that I will post common classroom questions and questions that push students beyond the lesson. Ron Larson, like most textbook authors, goes beyond the regular classroom questions to test if students truly understand the chapter lessons.
 

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