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prove
log(a,x)=log(b,x)/log(b,a)
first
Let log(a, x)=y
then write in exponent form
a^y = x
then take log (base b ) of both sides and evaluate
log(b, a^y) = log (b, x)
y*log(b, a) = log (b, x)........substitute y
log(a, x)*log(b, a) = log (b, x)
log(a, x)= log (b, x)/log(b, a)