Prove Inverse Trigonometric Functions

[nycmathguy]

I am having a hard time understanding what needs to be done with proving inverse trigonometric functions. For example, what is she doing in this video lesson?

 

[MathLover1]

prove: cos(sin^-1(x))=sqrt(1-x^2)

let sin^-1(x)=y

then cos(sin^-1(x))=cos(y) where -pi/2<= y<= pi/2 , then cos(y) >=0

use identity cos^2(y)+sin^2(y)=1..........solve for cos

cos^2(y)=1-sin^2(y)
cos(y)=sqrt(1-sin^2(y))......since sin^-1(x)=y, we can write that sin(y)=x =>sin^2(y)=x^2

substitute sin^2(y)=x^2 and sin^-1(x)=y in cos(y)=sqrt(1-sin^2(y)) and we have:

cos(sin^-1(x))=sqrt(1-x^2)

 

[nycmathguy]

prove: cos(sin^-1(x))=sqrt(1-x^2)

let sin^-1(x)=y

then cos(sin^-1(x))=cos(y) where -pi/2<= y<= pi/2 , then cos(y) >=0

use identity cos^2(y)+sin^2(y)=1..........solve for cos

cos^2(y)=1-sin^2(y)
cos(y)=sqrt(1-sin^2(y))......since sin^-1(x)=y, we can write that sin(y)=x =>sin^2(y)=x^2

substitute sin^2(y)=x^2 and sin^-1(x)=y in cos(y)=sqrt(1-sin^2(y)) and we have:

cos(sin^-1(x))=sqrt(1-x^2)

Your reply is better than Ms. Shaws' but still not clear enough for me to try on my own. Enough! Moving on.