Prove Inverse Trigonometric Functions

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Nov 23, 2021.

  1. nycmathguy

    nycmathguy

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    I am having a hard time understanding what needs to be done with proving inverse trigonometric functions. For example, what is she doing in this video lesson?

     
    nycmathguy, Nov 23, 2021
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  2. nycmathguy

    MathLover1

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    prove: cos(sin^-1(x))=sqrt(1-x^2)

    let sin^-1(x)=y

    then cos(sin^-1(x))=cos(y) where -pi/2<= y<= pi/2 , then cos(y) >=0

    use identity cos^2(y)+sin^2(y)=1..........solve for cos

    cos^2(y)=1-sin^2(y)
    cos(y)=sqrt(1-sin^2(y))......since sin^-1(x)=y, we can write that sin(y)=x =>sin^2(y)=x^2

    substitute sin^2(y)=x^2 and sin^-1(x)=y in cos(y)=sqrt(1-sin^2(y)) and we have:

    cos(sin^-1(x))=sqrt(1-x^2)

     
    MathLover1, Nov 23, 2021
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Your reply is better than Ms. Shaws' but still not clear enough for me to try on my own. Enough! Moving on.
     
    nycmathguy, Nov 24, 2021
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