Radical Equation

[nycmathguy]

Solve for x.

(2^(x - 4))^(1/3) = 16

 

[MathLover1]

(2^(x - 4))^(1/3) = 16........raise to power of 3

2^(x - 4)= 16^3...........write 16 as 2^4
2^(x - 4)= (2^4)^3

2^(x - 4)= 2^12 .........if base same, exponents are same too
x - 4= 12
x = 12+4
x = 16

 

[nycmathguy]

(2^(x - 4))^(1/3) = 16........raise to power of 3

2^(x - 4)= 16^3...........write 16 as 2^4
2^(x - 4)= (2^4)^3

2^(x - 4)= 2^12 .........if base same, exponents are same too
x - 4= 12
x = 12+4
x = 16

A job well-done.

How about this last algebra thread for now?

Insane Exponential Equation