Radioactive Decay

Discussion in 'Other Pre-University Math' started by nycmathguy, Oct 12, 2021.

  1. nycmathguy

    nycmathguy

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    20211012_174241.jpg

    In example 9, how much of the 10 pounds will remain in the year 2089? How much of
    the 10 pounds will remain after 125,000 years?

    Here is my set up:

    P = 10(1/2)^(t/24,100)

    Let me see.

    t = 2089 - 1986

    t = 103

    P = 10(1/2)^(103/24,100)

    Yes?

    How about 125,000 years?

    t = 125,000 - 1986

    t = 123,014

    P = 10(1/2)^(123,014/24,100)

    Correct set up?
     
    nycmathguy, Oct 12, 2021
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  2. nycmathguy

    MathLover1

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    Correct
     
    MathLover1, Oct 12, 2021
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    nycmathguy likes this.
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  3. nycmathguy

    nycmathguy

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    Thank you.
     
    nycmathguy, Oct 13, 2021
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