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Let me see.After factoring the denominator of the original function, the result is 1/(x + 3). We have removed the discontinuity at x = 3 because (x - 3) was canceled. In other words, we filled in the hole making the function continuous at x = 3. Yes? Still, I don't understand why the function is undefined. Are you saying the original function is undefined?
Let me see.
After factoring the denominator of the original function, the result is 1/(x + 3). We have removed the discontinuity at x = 3 because (x - 3) was canceled. In other words, we filled in the hole making the function continuous at x = 3. Yes? Still, I don't understand why the function is undefined. Are you saying the original function is undefined?
