write the trigonometric expressions in the following forms:
a) sqrt(a^2+b^2)*sin(B*theta +C)
b) sqrt(a^2+b^2)*cos(B*theta-C)
a* sin θ + b* cos θ ≡ R sin (θ + α) where R=sqrt(a^2+b^2)
91.
given: sin(θ )+cos(θ )
a)
sin(θ )+cos(θ ) =>a=1 and b=1, C=arctan (a/b)=arctan (1/1)=π/4
then r=sqrt(a^2+b^2)=sqrt(1^2+1^2)=sqrt(2)
sin(theta)+cos(theta) =sqrt(2) sin(θ + π/4)
b)
sin(θ )+cos(θ ) =sqrt(2)*cos(theta-π/4)
93. you can do it same way
