Set 1.2 Questions 34, 36, 38 David Cohen Rewrite without using absolute value notation. See attachment. [ATTACH=full]91[/ATTACH] [ATTACH=full]92[/ATTACH] Question 34 Since x > 4, the value inside is positive for both absolute value expressions added. | x - 3 | + | x - 4| x - 3 + x - 4 2x - 7 Question 36 Since x = 4, | x - 3 | is positive and | x - 4 | becomes 0. We have x - 3 + 0 = x - 3. Question 38 Since x < -3, | x + 1 | is negative. We also know that | x + 3 | is negative. We have -(x + 1) - 4(x + 3). -x - 1 - 4x - 12 -5x - 13 You say?