b.
To start we will use values of θ between 0° and 90° .
if h=5
s = 5cot(theta)
theta........................s = 5cot(theta)
0°...........................s = 5cot(0°)=
30°...........................s = 5cot(30°)=8.66
45°...........................s = 5cot(45°)=5
60°...........................s = 5cot(60°)=2.89
90°...........................s = 5cot(90°)=0
c.
minimum length is at 90°
d.
at the midpoint of the day: noon
