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Section 5.1


Question 22


sin^2 x•sec^2 x - sin^2 x


sin^2 x(sec^2 x - 1)


I know that sec^2 x - 1 = tan^2 x.


sin^2 x(tan^2 x)


sin^2 x (sin^2 x/cos^2 x)


sin^4 x/cos^2 x


Is this right?


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