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Section 5.1
Question 19
tan (theta) • cot (theta)/sec (theta)
I will back-substitute for x later.
Let x = theta
tan x = sin x/cos x
cot x = cos x/sin x
The numerator becomes
sin x/cos x • cos x sin x = 1
Our numerator is now 1.
We then have 1/sec x.
I know that 1/sec x = cos x.
Let x = theta
Answer: cos (theta).
You say?
Question 19
tan (theta) • cot (theta)/sec (theta)
I will back-substitute for x later.
Let x = theta
tan x = sin x/cos x
cot x = cos x/sin x
The numerator becomes
sin x/cos x • cos x sin x = 1
Our numerator is now 1.
We then have 1/sec x.
I know that 1/sec x = cos x.
Let x = theta
Answer: cos (theta).
You say?