Solve for a

[harpazo]

Given R = 1/[(1/a) + (1/b)].

Let me see.


LCD for [(1/a) + (1/b)] is ab.


I get (b + a)/(ab).


R = (b + a)/(ab)

(ab)R = b + a

abR - a = b

a(bR - 1) = b

a = b/(bR - 1)

You say?