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Solve for cos A
- Thread starter nycmathguy
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last line is incorrect
a^2-b^2-c^2= (-2bc)*cos(A)
(a^2-b^2-c^2)/(-2bc) = cos(A)
-(a^2-b^2-c^2)/(2bc) = cos(A)
(-a^2+b^2+c^2)/(2bc) = cos(A)
a^2-b^2-c^2= (-2bc)*cos(A)
(a^2-b^2-c^2)/(-2bc) = cos(A)
-(a^2-b^2-c^2)/(2bc) = cos(A)
(-a^2+b^2+c^2)/(2bc) = cos(A)
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I tried. I did my best. Can't get them all right.
