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The following number of questions has been posted here for anyone wanting or in need of extra practice as we visit precalculus.
(1+0.10/12)^(12t)=2.......simplify
(1.008333)^(12t)=2..........take log of both sides
log((1.008333)^(12t))=log(2)
(12t)log(1.008333)=log(2)
12t=log(2)/log(1.008333)
t=log(2)/(12log(1.008333))
t≈6.96031