nycmathguy Joined Jun 27, 2021 Messages 5,386 Reaction score 422 Apr 10, 2022 #1 Revisiting precalculus just for fun.
MathLover1 Joined Jun 27, 2021 Messages 2,989 Reaction score 2,884 Apr 10, 2022 #2 m^2=(1/2)(s^2+t^2)-(1/4)u^2 (1/4)u^2=(1/2)(s^2+t^2)-m^2 u^2=4(1/2)(s^2+t^2)-m^2 u^2=2(s^2+t^2)-m^2 u=sqrt(2(s^2+t^2)-m^2)
m^2=(1/2)(s^2+t^2)-(1/4)u^2 (1/4)u^2=(1/2)(s^2+t^2)-m^2 u^2=4(1/2)(s^2+t^2)-m^2 u^2=2(s^2+t^2)-m^2 u=sqrt(2(s^2+t^2)-m^2)
nycmathguy Joined Jun 27, 2021 Messages 5,386 Reaction score 422 Apr 10, 2022 #3 MathLover1 said: m^2=(1/2)(s^2+t^2)-(1/4)u^2 (1/4)u^2=(1/2)(s^2+t^2)-m^2 u^2=4(1/2)(s^2+t^2)-m^2 u^2=2(s^2+t^2)-m^2 u=sqrt(2(s^2+t^2)-m^2) Click to expand... Ok. No more bouncing around. We are doing calculus. So, let's stick to one course at a time. I would like for us to go through an entire college algebra textbook in the future, if you so desire to continue this journey.
MathLover1 said: m^2=(1/2)(s^2+t^2)-(1/4)u^2 (1/4)u^2=(1/2)(s^2+t^2)-m^2 u^2=4(1/2)(s^2+t^2)-m^2 u^2=2(s^2+t^2)-m^2 u=sqrt(2(s^2+t^2)-m^2) Click to expand... Ok. No more bouncing around. We are doing calculus. So, let's stick to one course at a time. I would like for us to go through an entire college algebra textbook in the future, if you so desire to continue this journey.