Solve For x...4

Discussion in 'Other Pre-University Math' started by nycmathguy, Apr 9, 2022.

  1. nycmathguy

    nycmathguy

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    Revisiting precalculus just for fun.
    Enjoy.

    IMG_20220409_181547.jpg
     
    nycmathguy, Apr 9, 2022
    #1
  2. nycmathguy

    MathLover1

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    b/(ax-1)-a/(bx-1)=0.........common denominator is(ax-1)(bx-1)

    b(bx-1)/((ax-1)(bx-1))-a(ax-1)/((ax-1)(bx-1))=0...........both sides multiply by (ax-1)(bx-1)

    b(bx-1)-a(ax-1)=0

    b^2*x-b-(a^2*x-a)=0

    b^2*x-b-a^2*x+a=0

    b^2*x-a^2*x=b-a

    (b^2-a^2)x=b-a

    x=(b-a)/(b^2-a^2)...........factor b^2-a^2=(b-a)(b+a)

    x=(b-a)/((b-a)(b+a))........simplify

    x=1/(b+a) where upload_2022-4-9_17-57-50.gif and upload_2022-4-9_17-58-37.gif
     

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    MathLover1, Apr 9, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    A nice walk through precalculus just for fun.
     
    nycmathguy, Apr 10, 2022
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