Solve for x. x^(x)^(5) = 100
I found this problem in a FB math group. There are so many FB math groups. I don't recall where this is posted. You can disregard the question if it is beyond precalculus. Take a look at the recently-posted word problems in the Basic Math forum.
this requires more knowledge beyond calculus III , advanced Calculus x^x^5 = 100......take log of both sides Rewrite the equation with 2ln (10 )/5x=u and x= 2ln(10)/u5 (2ln(10)/u5 )e^-u=1 ..........rewrite in Lambert form e^u*u=2ln(10)/5..........solve for u u=W[0](2ln(10)/5)...............substitute back u=2ln(10)/5x 2ln(10)/5x=W[0](2ln(10)/5).........solve for x 2ln(10)/W[0](2ln(10)/5)=5x x=2ln(10)/(W[0](2ln(10)/5)*5) x = 10^(1/5)->solution or, simplest way: Graph each side of the equation. The solution is the x-value of the point of intersection. x≈1.58489319
Wow! I saw the beginning video clip and quickly thought it was a simple algebra 2 problem. Considering what you said, this problem belongs in a different forum.