MathLover1 Joined Jun 27, 2021 Messages 2,989 Reaction score 2,884 Jun 20, 2022 #2 100/(1+e^(2x))=1 100=(1+e^(2x)) 1+e^(2x)=100 e^(2x)=100-1 e^(2x)=99 ln(e^(2x))=ln(99) (2x)ln(e)=ln(3^2*11) (2x)*1=ln(3^2)+ln(11) 2x=2log(3) + log(11) x=(2log(3) + log(11))/2 x=log(3) + log(11)/2
100/(1+e^(2x))=1 100=(1+e^(2x)) 1+e^(2x)=100 e^(2x)=100-1 e^(2x)=99 ln(e^(2x))=ln(99) (2x)ln(e)=ln(3^2*11) (2x)*1=ln(3^2)+ln(11) 2x=2log(3) + log(11) x=(2log(3) + log(11))/2 x=log(3) + log(11)/2
nycmathguy Joined Jun 27, 2021 Messages 5,386 Reaction score 422 Jun 20, 2022 #3 MathLover1 said: 100/(1+e^(2x))=1 100=(1+e^(2x)) 1+e^(2x)=100 e^(2x)=100-1 e^(2x)=99 ln(e^(2x))=ln(99) (2x)ln(e)=ln(3^2*11) (2x)*1=ln(3^2)+ln(11) 2x=2log(3) + log(11) x=(2log(3) + log(11))/2 x=log(3) + log(11)/2 Click to expand... Thanks. LaTex or Wolfram, please.
MathLover1 said: 100/(1+e^(2x))=1 100=(1+e^(2x)) 1+e^(2x)=100 e^(2x)=100-1 e^(2x)=99 ln(e^(2x))=ln(99) (2x)ln(e)=ln(3^2*11) (2x)*1=ln(3^2)+ln(11) 2x=2log(3) + log(11) x=(2log(3) + log(11))/2 x=log(3) + log(11)/2 Click to expand... Thanks. LaTex or Wolfram, please.