Solving Trigonometric Equations...5

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Dec 18, 2021.

  1. nycmathguy

    nycmathguy

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    Section 5.3

    Screenshot_20211216-022506_Samsung Notes.jpg

    IMG_20211218_180906.jpg

    IMG_20211218_180917.jpg

    IMG_20211218_181031.jpg

    IMG_20211218_181043.jpg
     
    nycmathguy, Dec 18, 2021
    #1
  2. nycmathguy

    MathLover1

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    30.
    general solutions are correct

    x=pi/3+2pi*k
    x=5pi/3+2pi*k

    but, you need solutions for the range 0<=x<=2pi (given interval [0,2pi]) and solutions are
    x=pi/3
    x=5pi/3

    Degrees:
    x=60°
    x=300°


    32.
    in interval [0,2pi]) solutions are
    Radians:
    x=0
    x=2pi


    Degrees:
    x=0°
    x=360°
     
    MathLover1, Dec 19, 2021
    #2
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  3. nycmathguy

    nycmathguy

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    1. Are you saying that [0, 2•pi) means all solutions in one revolution?

    2. Is my general solution correct for 32?
     
    nycmathguy, Dec 19, 2021
    #3
  4. nycmathguy

    MathLover1

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    yes
     
    MathLover1, Dec 19, 2021
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  5. nycmathguy

    nycmathguy

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    Very good. Time for Christmas music while working on some trigonometric equations. New questions posted soon.
     
    nycmathguy, Dec 19, 2021
    #5
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