Sound Intensity

Section 3.2
84 (a - c)



For part (a), I simply replace I with 1 and simplify. Yes?

For part (b), I simply replace I with 1/(100) and simplify. Yes?

Can you explain part (c)?

This ends our Section 3.2. We now move on to Section 3.3 or Properties of Logarithms.

 

a, b ->yes

c.
beta=10log(I/10^-12)

intensity of sound in part a is 1 and in part b is 10^-2 =1/100 => (1/100)100=1=> intensity of sound in part a is 100 times greater than intensity of sound in part b

in part a, beta=10log(1/10^-12)=120 decibels
in part b, beta=10log(10^-2/10^-12)=100 decibels=> the number of decibels is not 100 times as great

 

Interesting reply. Thanks. By the way, we are in Chapter 3, Section 3.2. Chapter 4 is Trigonometry. Just giving you a heads up.