Speed Enforcement

[nycmathguy]

Section 4.8

Can you set up part (b)?

 

[MathLover1]

part a)

L=250 is correct

m<A is NOT equal to m < B

tan(delta)=200/150 ...........< delta (inner angle in right triangle, upper corner to the left) is equal to <A as angles with one common leg and two other legs are parallel

tan(A)=tan(delta)=200/150

<A= tan^-1(200/150)

<A=53.13°

then <B=90-<A
<B=90-53.13°
<B=36.87°


part b)

given: speed s=35mph
L=250ft

convert ft to miles
250ft=0.0473485mil

convert h to seconds
1h=3600s

L=s*t

0.0473485mil=(35mil/3600s)*t

t=(0.0473485mil)/(35mil/3600s)

t=4.87 seconds

 

[nycmathguy]

part a)

L=250 is correct

m<A is NOT equal to m < B

tan(delta)=200/150 ...........< delta (inner angle in right triangle, upper corner to the left) is equal to <A as angles with one common leg and two other legs are parallel

tan(A)=tan(delta)=200/150

<A= tan^-1(200/150)

<A=53.13°

then <B=90-<A
<B=90-53.13°
<B=36.87°


part b)

given: speed s=35mph
L=250ft

convert ft to miles
250ft=0.0473485mil

convert h to seconds
1h=3600s

L=s*t

0.0473485mil=(35mil/3600s)*t

t=(0.0473485mil)/(35mil/3600s)

t=4.87 seconds

I sure wish I had your math skills. I would have so much fun solving math problems.

 

[nycmathguy]

part a)

L=250 is correct

m<A is NOT equal to m < B

tan(delta)=200/150 ...........< delta (inner angle in right triangle, upper corner to the left) is equal to <A as angles with one common leg and two other legs are parallel

tan(A)=tan(delta)=200/150

<A= tan^-1(200/150)

<A=53.13°

then <B=90-<A
<B=90-53.13°
<B=36.87°


part b)

given: speed s=35mph
L=250ft

convert ft to miles
250ft=0.0473485mil

convert h to seconds
1h=3600s

L=s*t

0.0473485mil=(35mil/3600s)*t

t=(0.0473485mil)/(35mil/3600s)

t=4.87 seconds

Great job as always.