Standing Waves

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Dec 27, 2021.

  1. nycmathguy

    nycmathguy

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    Section 5.4

    Screenshot_20211226-014356_Samsung Notes.jpg

    IMG_20211226_185932.jpg
     
    nycmathguy, Dec 27, 2021
    #1
  2. nycmathguy

    MathLover1

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    y[1]=A*cos(2pi(t/T-x/λ),

    y[2]=A*cos(2pi(t/T +x/λ),

    y[1]+y[2]=A*cos(2pi(t/T-x/λ))+A*cos(2pi(t/T +x/λ)

    y[1]+y[2]=A(cos((2πt)/T - (2πx)/λ)+cos((2πt)/T + (2 π x)/λ))

    y[1]+y[2]=A(2cos((2πt)/T) cos((2πx)/λ))

    y[1]+y[2]=2A(cos((2πt)/T) cos((2πx)/λ))
     
    MathLover1, Dec 27, 2021
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  3. nycmathguy

    nycmathguy

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    1. Did you skip any steps?

    2. How did you get
    y[1]+y[2]=A(2cos((2πt)/T) cos((2πx)/λ))?
     
    nycmathguy, Dec 27, 2021
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  4. nycmathguy

    MathLover1

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    y[1]+y[2]=A*cos(2pi(t/T-x/λ))+A*cos(2pi(t/T +x/λ).......factor out A
    y[1]+y[2]=A(cos(2pi(t/T-x/λ))+cos(2pi(t/T +x/λ))

    using cos(u-v) and cos(u+v) you prove that
    [​IMG]

    then you have [​IMG]
     
    MathLover1, Dec 27, 2021
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  5. nycmathguy

    nycmathguy

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    Originally, I thought about using cos(u - v) and
    cos(u + v) but was not sure what to do with A.
    Factoring comes in handy after prealgebra.
     
    nycmathguy, Dec 27, 2021
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