Reply to thread

44.


lim((e^(-2+h)-e^(-2))/h,h->0).........................(e^(-2+h)-e^(-2))/h=(e^h - 1)/(e^2 h)=((1/e^2)((e^h - 1)/h)

=lim(((1/e^2)((e^h - 1)/h),h->0).......take constant out


=(1/e^2)*lim((e^h - 1)/h),h->0)................apply L’Hopital’s rule (e^h - 1)/h=e^h /1


=(1/e^2)*lim(e^h /1),h->0)......substitute h=0


=(1/e^2)*(e^0 /1)


=(1/e^2)*(1 /1)


=(1/e^2)


so, [ATTACH=full]3388[/ATTACH]


Members online

No members online now.

Forum statistics

Threads
2,530
Messages
9,859
Members
696
Latest member
fairdistribution
Back
Top