State Period & Phase Shift

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Jul 2, 2022.

  1. nycmathguy

    nycmathguy

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    IMG_20220701_204740.jpg
     
    nycmathguy, Jul 2, 2022
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  2. nycmathguy

    MathLover1

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    y= 2cot((pi/3)x+pi/6))

    For f(x)=A*g(Bx-C)+D, where gt(x) is one of the basic trig functions, C/B is phase shift

    period= (periodicity of cot (x ))/B

    periodicity of cot (x ) is pi

    period: pi/ (pi/3)=3

    phase shift :

    in your case C=pi/6 and B=pi/3

    so phase shift is ( pi/6)(pi/3)=3/6= 1/2
     
    MathLover1, Jul 2, 2022
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  3. nycmathguy

    nycmathguy

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    Very cool. Understood.
     
    nycmathguy, Jul 2, 2022
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