Trigonometric Equations...1

[nycmathguy]

Section 5.5

 

[MathLover1]

again, given interval is [0,2π)
and solutions are:
x = 0
x = π/3
x = (5π)/3

 

[nycmathguy]

again, given interval is [0,2π)
and solutions are:
x = 0
x = π/3
x = (5π)/3

Isn't x = 0 the same as x = 2π in terms of the solution here?

 

[MathLover1]

x = 0 is NOT the same as x=2π in terms of the solution

2π is not solution because given interval is [0,2π), so x must be less than 2pi

 

[nycmathguy]

x = 0 is NOT the same as x=2π in terms of the solution

2π is not solution because given interval is [0,2π), so x must be less than 2pi

Yes, you are right. I see that [0,2π) means that 2pi
cannot be the answer.