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Section 5.4
Question 70
Use: cos(x+A)=cosx.cosA–sinx.sinA
Let A = pi
cos(x + pi) = cosx(-1) - sinx(0)
cos(x + pi) = -cosx
-cosx - cosx - 1 = 0
-2cos x - 1 = 0
-2 cos x = 1
cos x = -1/2
Solutions from 0 to 2pi but not including 2pi:
x = 2pi/3, 4pi/3
You say?
Question 70
Use: cos(x+A)=cosx.cosA–sinx.sinA
Let A = pi
cos(x + pi) = cosx(-1) - sinx(0)
cos(x + pi) = -cosx
-cosx - cosx - 1 = 0
-2cos x - 1 = 0
-2 cos x = 1
cos x = -1/2
Solutions from 0 to 2pi but not including 2pi:
x = 2pi/3, 4pi/3
You say?