- Joined
- Jun 27, 2021
- Messages
- 5,386
- Reaction score
- 422
David Cohen Textbook Questions.
Enjoy.
Enjoy.
sin^2(theta)=(2x)^2
sin^2(theta)=4x^2
cos^2(theta)=3^2
cos^2(theta)=9
tan^2(theta)=sin^2(theta)/cos^2(theta)=4x^2/9
The legs have lengths 2x and 3 so, by the Pythagorean formula, the hypotenuse has length sqrt(4x^2+ 9).
sin(theta)= 2x/sqrt(4x^2+ 9) so sin^2(theta)= 4x^2/(4x^2+ 9)
cos(theta)= 3/sqrt(4x^2+ 9) so cos^2(theta)= 9/(4x^2+ 9)
tan(theta)= 2x/3 so tan^2(theta)= 4x^2/9.