Age...2

Discussion in 'Algebra' started by nycmathguy, Feb 15, 2022.

  1. nycmathguy

    nycmathguy

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    I want to know if my set up is correct.

    1. In 20 years, Kayleen will be four times older than she is today. What is her current age?

    Let x = Kayleen's current age.
    Let x + 20 = Kayleen's age in 20 years.

    x + 20 = 4x

    You say?

    2. John is twice as old as his friend Peter. Peter is 5 years older than Alice. In 5 years, John will be three times as old as Alice. How old is Peter now?

    John's age now = 2(x + 5)

    Peter's age now = x + 5

    Alice's age now = x

    2(x + 5) = 3x

    Let me try this one.

    2x + 10 = 3x

    10 = 3x - 2x

    10 = x

    Peter = x + 5 or 10 + 5 = 15 years old.

    Yes?
     
    nycmathguy, Feb 15, 2022
    #1
  2. nycmathguy

    MathLover1

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    correct
     
    MathLover1, Feb 15, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Check point.
     
    nycmathguy, Feb 15, 2022
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