Air Navigation

[nycmathguy]

Section 4.8

Question 38

I see a right triangle.

Let one leg = 160

Let the other leg = 85

Let x = our bearing

tan x = 85/160

arctan(tan x) = arctan (85/160)

x = 27.98°

You say?

 

[MathLover1]

correct

 

[nycmathguy]

correct

Like I said in the previous reply, the entire weekend will be dedicated to bearing problems. In fact, I think there are several bearing questions in the David Cohen textbook. I will also check Cohen's book for extra bearing problems. Are you ready to bear bearing? LOL